Joe Mecha #427
Joe Mecha #427
Conversation
There was a problem hiding this comment.
Overall, strong work and effort! Very nice job working on the challenges at the end- all the effort there will pay off at Turing, being familiar with code challenges, breaking those problems apart, and digging in to research. Keep up the practice and experimentation!
| def add_topping(topping) | ||
| @toppings << topping | ||
| end | ||
|
|
There was a problem hiding this comment.
Nice attribute/method interactions here!
| end | ||
| end | ||
|
|
||
| ten_speckled_frogs(10) |
There was a problem hiding this comment.
Nice job seeing all the conditions to hit here. A next step could be to model this like a little ruby program, gathering some user input to run in your function.
| print "Please enter the word(s) you want to encode: " | ||
| string = gets.chomp | ||
| print "Enter the number of characters to shift by (ex. 3 shifts A to D; -3 shifts A to X): " | ||
| shift_value = gets.chomp.to_i |
There was a problem hiding this comment.
Nice job leveraging user input here! Also, way to stick with this challenge and push through! Seeing loots of good progress across the different cipher files. Some of this stuff- you can just find the answers out there, but grappling with it, breaking code, and experimentation are the best ways to learn the ins and outs- very well done here.
There was a problem hiding this comment.
Mason -- thanks for the encouragement here, and for reviewing my all of my work -- cheers!
|
|
||
| def encode | ||
| cipher_hash = {"A" => 0, "B" => 1, "C" => 2, "D" => 3, "E" => 4, "F" => 5 "G" => 6, "H" => 7, "I" => 8, "J" => 9, "K" => 10, "L" => 11, "M" => 12, "N" => 13, "O" => 14, "P" => 15, "Q" => 16, "R" => 17, "S" => 18, "T" => 19, "U" => 20, "V" => 21, "W" => 22, "X" => 23, "Y" => 24, "Z" => 25} | ||
| cipher_array = ["A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"] |
There was a problem hiding this comment.
arrays are just hashes where the 'key' is the index number, and the element is the value. If that doesn't make sense right way, just something to stew on.
| row_counter -= 1 | ||
| end | ||
| end | ||
|
|
There was a problem hiding this comment.
Way to stay organized! Loops within loops can get hairy.
| print "FizzBuzz, " | ||
| # For any number that is a multiple of 3, print 'Fizz' | ||
| elsif (a % 3) == 0 && (a % 5) != 0 | ||
| print "Fizz, " |
There was a problem hiding this comment.
You don't need the second part of the conditionals here- if both applied, it'd be swooped up by your first condition! You can just run the second 2 conditions checking for the 0 value of a modulo, rather than needing to see if it != 0.
Mod 1 prework completed!