[PhpParser] Alternative PR for findInstancesOfScoped() to keep existing performance

[samsonasik]

Alternative PR for #6323 , make it allow FunctionLike in array of nodes[0]:

1. Keep hasInstancesOfInFunctionLikeScoped as is for performance reason
2. Modify the method to allow single $nodes, as FunctionLike reuse

    /**
     * @api to be used
     *
     * @template T of Node
     * @param Node[] $nodes
     * @param class-string<T>|array<class-string<T>> $types
     * @return T[]
     */
    public function findInstancesOfScoped(array $nodes, string|array $types): array
    {
        // here verify only pass single nodes as FunctionLike
        if (count($nodes) === 1
            && ($nodes[0] instanceof ClassMethod || $nodes[0] instanceof Function_ || $nodes[0] instanceof Closure)) {
            $nodes = (array) $nodes[0]->stmts;
        }

        if (is_string($types)) {
            $types = [$types];
        }

        /** @var T[] $foundNodes */
        $foundNodes = [];

        $this->simpleCallableNodeTraverser->traverseNodesWithCallable(
            $nodes,
            static function (Node $subNode) use ($types, &$foundNodes): ?int {
                if ($subNode instanceof Class_ || $subNode instanceof Function_ || $subNode instanceof Closure) {
                    return NodeTraverser::DONT_TRAVERSE_CURRENT_AND_CHILDREN;
                }

                foreach ($types as $type) {
                    if ($subNode instanceof $type) {
                        $foundNodes[] = $subNode;
                        return null;
                    }
                }

                return null;
            }
        );

        return $foundNodes;
    }

3. Then, in findInstancesOfInFunctionLikeScoped, change to just call it:

    public function findInstancesOfInFunctionLikeScoped(
        ClassMethod | Function_ | Closure $functionLike,
        string|array $types
    ): array {
        return $this->findInstancesOfScoped([$functionLike], $types);
    }

Closes #6323

[samsonasik]

All checks have passed 🎉 @TomasVotruba it is ready to review.

[TomasVotruba]

Looks good, thanks 👍