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Add Dijkstra's algorithm for shortest paths
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from typing import Dict, List, Tuple | ||
import heapq | ||
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def dijkstra(graph: Dict[str, Dict[str, int]], start: str) -> Tuple[Dict[str, int], Dict[str, str]]: | ||
""" | ||
Implements Dijkstra's algorithm for finding the shortest path in a weighted graph. | ||
Args: | ||
graph (Dict[str, Dict[str, int]]): A dictionary representing the graph. | ||
Keys are node names, values are dictionaries | ||
of neighboring nodes and their distances. | ||
start (str): The starting node. | ||
Returns: | ||
Tuple[Dict[str, int], Dict[str, str]]: A tuple containing two dictionaries: | ||
1. Shortest distances from start to each node. | ||
2. Previous node in the optimal path from start to each node. | ||
""" | ||
distances = {node: float('infinity') for node in graph} | ||
distances[start] = 0 | ||
previous = {node: None for node in graph} | ||
pq = [(0, start)] | ||
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while pq: | ||
current_distance, current_node = heapq.heappop(pq) | ||
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if current_distance > distances[current_node]: | ||
continue | ||
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for neighbor, weight in graph[current_node].items(): | ||
distance = current_distance + weight | ||
if distance < distances[neighbor]: | ||
distances[neighbor] = distance | ||
previous[neighbor] = current_node | ||
heapq.heappush(pq, (distance, neighbor)) | ||
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return distances, previous | ||
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def get_path(previous: Dict[str, str], start: str, end: str) -> List[str]: | ||
""" | ||
Reconstructs the path from start to end using the previous node dictionary. | ||
Args: | ||
previous (Dict[str, str]): Dictionary of previous nodes in the optimal path. | ||
start (str): The starting node. | ||
end (str): The ending node. | ||
Returns: | ||
List[str]: The path from start to end. | ||
""" | ||
path = [] | ||
current = end | ||
while current: | ||
path.append(current) | ||
current = previous[current] | ||
return path[::-1] | ||
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# Example usage and test case | ||
if __name__ == "__main__": | ||
# Example graph | ||
graph = { | ||
'A': {'B': 4, 'C': 2}, | ||
'B': {'A': 4, 'C': 1, 'D': 5}, | ||
'C': {'A': 2, 'B': 1, 'D': 8, 'E': 10}, | ||
'D': {'B': 5, 'C': 8, 'E': 2, 'F': 6}, | ||
'E': {'C': 10, 'D': 2, 'F': 3}, | ||
'F': {'D': 6, 'E': 3} | ||
} | ||
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start_node = 'A' | ||
end_node = 'F' | ||
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distances, previous = dijkstra(graph, start_node) | ||
path = get_path(previous, start_node, end_node) | ||
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print(f"Shortest distances from {start_node}: {distances}") | ||
print(f"Shortest path from {start_node} to {end_node}: {' -> '.join(path)}") | ||
print(f"Total distance: {distances[end_node]}") | ||
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# Test cases | ||
def test_dijkstra(): | ||
# Test case 1: Simple graph | ||
graph1 = { | ||
'A': {'B': 1, 'C': 4}, | ||
'B': {'A': 1, 'C': 2, 'D': 5}, | ||
'C': {'A': 4, 'B': 2, 'D': 1}, | ||
'D': {'B': 5, 'C': 1} | ||
} | ||
distances1, previous1 = dijkstra(graph1, 'A') | ||
assert distances1 == {'A': 0, 'B': 1, 'C': 3, 'D': 4} | ||
assert get_path(previous1, 'A', 'D') == ['A', 'B', 'C', 'D'] | ||
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# Test case 2: Disconnected graph | ||
graph2 = { | ||
'A': {'B': 1}, | ||
'B': {'A': 1}, | ||
'C': {'D': 1}, | ||
'D': {'C': 1} | ||
} | ||
distances2, previous2 = dijkstra(graph2, 'A') | ||
assert distances2 == {'A': 0, 'B': 1, 'C': float('infinity'), 'D': float('infinity')} | ||
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print("All test cases passed!") | ||
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test_dijkstra() |