Bisection method calculator in python
url : http://jhhemal.me
you have to use python's mathmetical expression here.
f(x) = (4 * sin(x)) - (e**x)
suppose, I have a function like x^5 + x^3 - 1, then i have to use
f(x) = x**5 + x**3 - 1
Return the sqrt of x
Return the ln(x)
Return the arc cosine of x, in radians.
Return the arc sine of x, in radians.
Return the arc tangent of x, in radians.
Return the cosine of x radians.
Return the sine of x radians.
Return the tangent of x radians.
Return the inverse hyperbolic cosine of x.
Return the inverse hyperbolic sine of x.
Return the inverse hyperbolic tangent of x.
Return the hyperbolic cosine of x.
Return the hyperbolic sine of x.
Return the hyperbolic tangent of x.
The mathematical constant π = 3.141592…, to available precision.
The mathematical constant e = 2.718281…, to available precision.