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Questions about Eq.8 #16

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OnlyForWW opened this issue Jun 5, 2023 · 1 comment
Open

Questions about Eq.8 #16

OnlyForWW opened this issue Jun 5, 2023 · 1 comment

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@OnlyForWW
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I would like to ask how n^2 in Eq.8 was obtained, or could you please explain in detail the calculation process of Eq.8.
Thank you very much
@HantingChen
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Sorry for the mistake, the n^2 should be (2n+1)^2. The Eq.6 is summed accross two dimesnion i and j, and each dimension has 2n+1 values. Therefore, the computation complexity is (2n+1)^2.

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@HantingChen @OnlyForWW