How to execute flow with manually passed flow_run_id is it possible

[santosh614696]

Bug summary

import asyncio
from prefect import task,flow
from prefect.task_runners import ConcurrentTaskRunner

@task
async def task1(data:str):
   print(f"task1 started: {data}")
   await asyncio.sleep(60)
   return "success"
   
@task
async def MainTask():
   print("Main task started")
return "success"

@task
async def task3(data:str):
   print(f"task3 started: {data}")
   await asyncio.sleep(60)
   return "success"
   
@flow(name="Subflow")
async def task2(data:str):
   print(f"task2 subflow started: {data}")
   await asyncio.sleep(60)
   return "success"
   
@flow(task_runner=ConcurrentTaskRunner())
async def mainflow():
   a=await MainTask.submit()
   b=await task1.submit(a)
   c=await task3.submit(a)
   d=await task2(a)
if __name__=="__main__":
   asyncio.run(mainflow())

Version info (prefect version output)

Version:             2.20.1
API version:         0.8.4
Python version:      3.12.3
Git commit:          f6bebfca
Built:               Fri, Aug 9, 2024 10:35 AM
OS/Arch:             linux/aarch64
Profile:             default
Server type:         ephemeral
Server:
  Database:          postgresql

Additional context

How to execute flow with manually passed flow_run_id(uuid) is it possible?

[zzstoatzz]

hi @santosh614696 - looks like this is more of a question than an issue! feel free to clarify what you mean by this

How to execute flow with manually passed flow_run_id(uuid) is it possible?

in the new discussion! i.e. what flow run id are you manually passing? and from where?

[santosh614696]

Yes its a question.

For every flow execution there will be UUID created called flow_run_id can we pass UUID using parameter while executing the flow was the question?