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delete_node_in_list.cpp
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delete_node_in_list.cpp
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/*
* Copyright(c) 2019 Jiau Zhang
* For more information see <https://github.com/JiauZhang/algorithms>
*
* This repo is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation
*
* It is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with THIS repo. If not, see <http://www.gnu.org/licenses/>.
*/
#include <iostream>
using namespace std;
struct ListNode
{
int m_nValue;
ListNode* m_pNext;
};
ListNode* add_to_head(ListNode** pHead, int value)
{
if(pHead) {
if(*pHead) {
ListNode* pHead_ = *pHead;
*pHead = new ListNode();
(*pHead)->m_nValue = value;
(*pHead)->m_pNext = pHead_;
} else {
*pHead = new ListNode();
(*pHead)->m_nValue = value;
}
return *pHead;
}
}
//此函数不进行安全检查
ListNode* find_prev(ListNode* root, ListNode* find)
{
ListNode* prev;
while(root->m_pNext!=find)
root = root->m_pNext;
prev = root;
return prev;
}
//主要思想就是,如果此节点不是链表中最后一个
//把它的下一个复制过来,然后当前的指针指向下一个的下一个
//最后删除下一个
void DeleteNode(ListNode** pListHead, ListNode* pToBeDeleted)
{
if(pListHead) {
if(*pListHead) {
if(*pListHead==pToBeDeleted) { //如果这个节点在头部
/*if(pToBeDeleted->m_pNext==NULL) { //如果这个节点唯一的
*pListHead = NULL;
delete pToBeDeleted;
} else {
*pListHead = pToBeDeleted->m_pNext;
delete pToBeDeleted;
}*/
//可以简化代码
*pListHead = pToBeDeleted->m_pNext;
delete pToBeDeleted;
} else if(pToBeDeleted->m_pNext==NULL) { //如果此节点在尾部,只能从头遍历
ListNode* prev = find_prev(*pListHead, pToBeDeleted);
prev->m_pNext = NULL;
delete pToBeDeleted;
} else { //只剩下在中间部分的情况了
ListNode* pNext = pToBeDeleted->m_pNext;
ListNode* pNextNext = pNext->m_pNext;
pToBeDeleted->m_nValue = pNext->m_nValue;
pToBeDeleted->m_pNext = pNextNext;
delete pNext;
}
}
}
}
void print_list_head_to_tail(ListNode* pHead)
{
if(pHead) {
ListNode* head = pHead;
cout << head->m_nValue << ' ';
while(head->m_pNext) {
head = head->m_pNext;
cout << head->m_nValue << ' ';
}
cout << endl;
}
}
//这个程序有个假设,那就是我们给出的节点一定就在此链表中
int main(int argc, char** argv)
{
ListNode* root = NULL;
ListNode* node6 = add_to_head(&root, 6);
ListNode* node5 = add_to_head(&root, 5);
ListNode* node4 = add_to_head(&root, 4);
ListNode* node3 = add_to_head(&root, 3);
ListNode* node2 = add_to_head(&root, 2);
ListNode* node1 = add_to_head(&root, 1);
print_list_head_to_tail(root);
DeleteNode(&root, node3);
// DeleteNode(&root, node4); 与下边的程序同样的问题
print_list_head_to_tail(root);
//由于为了实现 O(1) 的删除效率,所以删除node5的时候其实node6已经不存在了
//所以执行删除node6才会出错
DeleteNode(&root, node5);
//DeleteNode(&root, node6);替换为再次删除node5才可以,因为此时它在尾部
DeleteNode(&root, node5);
print_list_head_to_tail(root);
DeleteNode(&root, node1);
print_list_head_to_tail(root);
DeleteNode(&root, node2);
DeleteNode(&root, node3);
print_list_head_to_tail(root);
return 0;
}